Number
|
Method
|
Example
|
7
|
Subtract 2 times the last digit from remaining truncated
number. Repeat the step as necessary. If the result is divisible by 7, the
original number is also divisible by 7
|
Check for 945: : 94-(2*5)=84. Since 84 is divisible by 7, the
original no. 945 is also divisible
|
13
|
Add 4 times the last digit to the remaining truncated number.
Repeat the step as necessary. If the result is divisible by 13, the original
number is also divisible by 13
|
Check for 3146:: 314+ (4*6) = 338:: 33+(4*8) = 65. Since 65 is
divisible by 13, the original no. 3146 is also divisible
|
17
|
Subtract 5 times the last digit from remaining truncated
number. Repeat the step as necessary. If the result is divisible by 17, the
original number is also divisible by 17
|
Check for 2278:: 227-(5*8)=187. Since 187 is divisible by 17,
the original number 2278 is also divisible.
|
19
|
Add 2 times the last digit to the remaining truncated number.
Repeat the step as necessary. If the result is divisible by 19, the original
number is also divisible by 19
|
Check for 11343:: 1134+(2*3)= 1140. (Ignore the 0):: 11+(2*4)
= 19. Since 19 is divisible by 19, original no. 11343 is also divisible
|
23
|
Add 7 times the last digit to the remaining truncated number.
Repeat the step as necessary. If the result is divisible by 23, the original
number is also divisible by 23
|
Check for 53935:: 5393+(7*5) = 5428 :: 542+(7*8)= 598:: 59+
(7*8)=115, which is 5 times 23. Hence 53935 is divisible by 23
|
29
|
Add 3 times the last digit to the remaining truncated number.
Repeat the step as necessary. If the result is divisible by 29, the original
number is also divisible by 29
|
Check for 12528:: 1252+(3*8)= 1276 :: 127+(3*6)= 145:: 14+
(3*5)=29, which is divisible by 29. So 12528 is divisible by 29
|
31
|
Subtract 3 times the last digit from remaining truncated
number. Repeat the step as necessary. If the result is divisible by 31, the
original number is also divisible by 31
|
Check for 49507:: 4950-(3*7)=4929 :: 492-(3*9) :: 465::
46-(3*5)=31. Hence 49507 is divisible by 31
|
37
|
Subtract 11 times the last digit from remaining truncated
number. Repeat the step as necessary. If the result is divisible by 37, the
original number is also divisible by 37
|
Check for 11026:: 1102 - (11*6) =1036. Since 103 - (11*6) =37
is divisible by 37. Hence 11026 is divisible by 37
|
41
|
Subtract 4 times the last digit from remaining truncated
number. Repeat the step as necessary. If the result is divisible by 41, the
original number is also divisible by 41
|
Check for 14145:: 1414 - (4*5) =1394. Since 139 - (4*4) =123
is divisible by 41. Hence 14145 is divisible by 41
|
43
|
Add 13 times the last digit to the remaining truncated number.
Repeat the step as necessary. If the result is divisible by 43, the original
number is also divisible by 43.*This
process becomes difficult for most of the people because of multiplication with 13.
|
Check for 11739:: 1173+(13*9)= 1290:: 129 is divisible by 43.
0 is ignored. So 11739 is divisible by 43
|
47
|
Subtract 14 times the last digit from remaining truncated
number. Repeat the step as necessary. If the result is divisible by 47, the
original number is also divisible by 47. This
too is difficult to operate for people who are not comfortable with table of
14.
|
Check for 45026:: 4502 - (14*6) =4418. Since 441 - (14*8)
=329, which is 7 times 47. Hence 45026 is divisible by 47
|
Notes:
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