Monday, September 24, 2012


The sum of 1/4,1/9,1/16....1/n2 is :
(1)
less than 1
(2) 
greater than 1
(3)
equal to 1 or less than 1
(4)
equal to 1/n2 (n + 2)
The right answer is Option (1).
¼ + 1/9 + 1/16 +…+ 1/n2
Consider ¼:
¼ = 1/(2 x 2) < 1/(1 x 2) because ½ < 1
Similarly, 1/9 = 1/(3 x 3) < 1/(2 x 3)
Since 1/3 < ½
1/16 = 1/(4 x 4) < 1/(3 x 4)
Because ¼ < 1/3
……………………………………………………..
……………………………………………………..
1/n2 = 1/(nxn) < 1/(n – 1)n
Since 1/n < 1/(n – 1)
¼ + 1/9 + …+ 1/n2 < 1/(1 x 2) + 1/(2 x 3) + … + 1/[(n – 1)n]
i.e. ¼ + 1/9 + 1/16 + … + 1/n2 < (1/1 – ½) + (1/2 – 1/3) +…+ [1/(n – 1) – 1/n]
i.e. ¼ + 1/9 + 1/16 +… + 1/n2 < 1/1 – 1/n which is less than 1.
Hence, the given sum is less than 1 only.
Answer: (1)
What is the digit in the unit place of  3946252 + 734733 ?
(1)
8
(2) 
7
(3)
6
(4)
4
The right answer is Option (1).
3946252 + 734733
First we will find the unit digit of 3946252.
Divide 46, by 4, we get 2 as remainder.
Actual remainder (2)252
Again dividing (2)252  by 4, we get 0 as remainder. And ‘9’ is an odd digit number. So, the last digit of 3946252 will be 1.
Last digit of 734733 Þ By dividing 47 by 4, we get 3 or – 1 as a remainder.
Now, (– 1) odd, when divided by 4 will give – 1 or 3 as remainder.
So, the last digit of 734733 will be.
Last digit of 3 ´ 3 ´ 3 = i.e. 7.
So, the last digit is 1 + 7 = 8. Answer: (1)
The expression 333555 + 555333 is divisible by:
(1)
2
(2) 
3
(3)
37
(4)
All of these
The right answer is Option (4).
333555 + 555333
Check it by option.
The last digit of 333555 will be odd, and the last digit of 555333 will be odd.
odd + odd Þ even
So, the last digit is even, which is divisible by 2.
Both the numbers are individually divisible by 3. So 333555 + 555333 is divisible by 3.
And similarly, both the numbers are divisible by 37, so, 333555 + 555333 is divisible by 37.
Hence this expression is divisible by all three numbers.   Answer : (4)
Note : If the number consists of same in the multiples of 3, then it is always a multiple of 37
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So, the last digit is 1 + 7 = 8. Answer: (1)


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